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Simple Projectile Motion Calculator

Maximum Height Equation:

\[ h_{max} = \frac{(v \sin \theta)^2}{2g} \]

m/s
degrees
m/s²

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1. What is Maximum Height in Projectile Motion?

The maximum height (hmax) is the highest vertical position reached by a projectile during its flight. It occurs when the vertical component of the velocity becomes zero.

2. How Does the Calculator Work?

The calculator uses the maximum height equation:

\[ h_{max} = \frac{(v \sin \theta)^2}{2g} \]

Where:

Explanation: The equation calculates the peak height reached by a projectile launched at an angle θ with initial velocity v, considering gravity's effect.

3. Importance of Maximum Height Calculation

Details: Calculating maximum height is essential in physics, engineering, and ballistics for understanding projectile behavior, optimizing trajectories, and safety considerations.

4. Using the Calculator

Tips: Enter initial velocity in m/s, launch angle in degrees (0-90), and gravity in m/s² (9.81 for Earth). All values must be positive.

5. Frequently Asked Questions (FAQ)

Q1: What angle gives maximum height for a given velocity?
A: 90 degrees (straight up) gives the maximum height, but results in no horizontal distance.

Q2: Does mass affect maximum height?
A: No, in ideal projectile motion (neglecting air resistance), mass doesn't affect maximum height.

Q3: How does gravity affect maximum height?
A: Higher gravity reduces maximum height as it accelerates the projectile downward more quickly.

Q4: What if I need to calculate range instead of height?
A: The range equation is different: \( R = \frac{v^2 \sin(2\theta)}{g} \)

Q5: Does this consider air resistance?
A: No, this is the ideal case. Real-world calculations may need to account for air resistance.

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