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Projectile Motion Calculator With Drag

Projectile Motion with Drag Equations:

\[ x = \frac{v \cos \theta}{k} (1 - e^{-k t}) \] \[ y = \frac{1}{k} \left(v \sin \theta + \frac{g}{k}\right) (1 - e^{-k t}) - \frac{g t}{k} \]

m/s
degrees
1/s
s
m/s²

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1. What is Projectile Motion With Drag?

Projectile motion with drag accounts for air resistance affecting the trajectory of an object moving through the air. Unlike ideal projectile motion, drag causes the path to be asymmetrical and reduces both range and maximum height.

2. How Does the Calculator Work?

The calculator uses the following equations for projectile motion with linear drag:

\[ x = \frac{v \cos \theta}{k} (1 - e^{-k t}) \] \[ y = \frac{1}{k} \left(v \sin \theta + \frac{g}{k}\right) (1 - e^{-k t}) - \frac{g t}{k} \]

Where:

Explanation: These equations describe the position of a projectile experiencing a drag force proportional to its velocity.

3. Importance of Drag in Projectile Motion

Details: Drag significantly affects projectile trajectories, especially for objects with large surface areas or low mass, and at higher velocities. Accounting for drag is essential for accurate predictions in ballistics, sports physics, and engineering applications.

4. Using the Calculator

Tips: Enter initial velocity in m/s, launch angle in degrees (0-90), drag coefficient (typically 0.01-0.5 for most objects), time in seconds, and gravity (9.81 m/s² on Earth). All values must be positive.

5. Frequently Asked Questions (FAQ)

Q1: What is a typical drag coefficient value?
A: For most objects, k ranges from 0.01 to 0.5 1/s. Smaller values indicate less drag, while larger values indicate more significant air resistance.

Q2: How does drag affect the trajectory?
A: Drag reduces both range and maximum height, makes the descent steeper than the ascent, and causes the projectile to fall more vertically at the end.

Q3: Why is the drag model linear?
A: This calculator uses a simplified linear drag model (force proportional to velocity). Real-world drag is often quadratic (proportional to velocity squared), but linear models are easier to solve and useful for many applications.

Q4: Can I calculate maximum height with drag?
A: Yes, but it requires solving for when vertical velocity becomes zero. The calculator shows position at specific times.

Q5: What are the limitations of this model?
A: It assumes constant drag coefficient, no wind, no lift forces, and a flat Earth. For precise calculations, more complex models are needed.

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