Orbital Period Equation:
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The orbital period is the time a given astronomical object takes to complete one orbit around another object. For Earth satellites, it's the time to complete one full orbit around Earth.
The calculator uses Kepler's third law:
Where:
Explanation: The equation shows that the orbital period squared is proportional to the semi-major axis cubed (Kepler's third law).
Details: Calculating orbital periods is essential for satellite operations, space mission planning, and understanding celestial mechanics.
Tips: Enter the semi-major axis in meters (distance from Earth's center to satellite's farthest point). The value must be greater than Earth's radius (~6,371 km).
Q1: What's the period at geostationary orbit?
A: At ~35,786 km altitude (42,164 km from Earth's center), the period is exactly 1 sidereal day (23h 56m 4s).
Q2: How does altitude affect period?
A: Higher orbits have longer periods. Doubling the orbital radius increases the period by about 2.8 times.
Q3: What's the minimum orbital period?
A: The theoretical minimum is about 84 minutes (just above Earth's surface), but atmospheric drag makes low orbits impractical.
Q4: Does the satellite's mass affect the period?
A: No, the period depends only on the primary body's mass (Earth) and the semi-major axis.
Q5: How to convert to hours/minutes?
A: Divide seconds by 3600 for hours, or by 60 for minutes. For example, 5400s = 1.5h = 90m.